document.write( "Question 1189908: To compare the results of boys and girls in a class, a special test was given to 50 boys who averaged 67.4 with standard deviation of 5, and 50 girls averaged 62.8 with standard deviation of 4.6
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document.write( "a) Test, at alpha=0.05, whether the difference is significant or not.
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document.write( "b) Test if the difference is 3 \n" );
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Algebra.Com's Answer #821430 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Ho: mu boy=mu girl \n" ); document.write( "Ha: mu boy NE mu girl \n" ); document.write( "alpha=0.05 p{reject Ho|Ho true} \n" ); document.write( "test is 2 sample t-test \n" ); document.write( "df=98 \n" ); document.write( "critical value is 1.985 \n" ); document.write( "calculation t=(diff means/SE) \n" ); document.write( "=(67.4-62.8)/sqrt (s1^2/n1)+(s2^2/n2)) \n" ); document.write( "=4.6/sqrt [(25/50+(21.16/50)] \n" ); document.write( "=4.6/.96=4.79 \n" ); document.write( "reject Ho and conclude there is a difference between the two at the 0.05 level. \n" ); document.write( "p-value <0.0001 \n" ); document.write( "- \n" ); document.write( "For difference of 3, \n" ); document.write( "mu boy-mu girl <=3 \n" ); document.write( "mu boy-mu girl NE>=3 \n" ); document.write( "t-value is 3/0.96=3.125, so reject that hypothesis and say that the difference is greater than 3. \n" ); document.write( " \n" ); document.write( " |