document.write( "Question 1189920: A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The premium antifreeze solution contains 85% pure antifreeze. The company wants to obtain 255 gallons of a mixture that contains 30% pure antifreeze. How many gallons of water and how many gallons of the premium antifreeze solution must be mixed? \n" ); document.write( "
Algebra.Com's Answer #821429 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x*0.85=0.85x pure (100%) \n" ); document.write( "end is 255*0.30=76.5 gallons pure \n" ); document.write( "so 0.85x=76 \n" ); document.write( "x=89.41 gallons of the 85% antifreeze and 165.59 gallons of water. \n" ); document.write( " |