document.write( "Question 1189913: Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $55. For one performance, 30 advance tickets and 40 same-day tickets were sold. The total amount paid for the tickets was $1900. What was the price of each kind of ticket? \n" ); document.write( "
Algebra.Com's Answer #821415 by Theo(13342)\"\" \"About 
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a = number of advance tickets.
\n" ); document.write( "s = number of same day tickiets.\r
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\n" ); document.write( "\n" ); document.write( "equations that need to be solved simultaneously are:
\n" ); document.write( "a + s = 55
\n" ); document.write( "30a + 40s = 1900\r
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\n" ); document.write( "\n" ); document.write( "multiply both sides of the first equation by 30 and leave the second equatin as is to get:
\n" ); document.write( "30a + 30s = 1650
\n" ); document.write( "30a + 40s = 1900\r
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\n" ); document.write( "\n" ); document.write( "subtract the first equation from the second to get:
\n" ); document.write( "10s = 250
\n" ); document.write( "solve for s to get:
\n" ); document.write( "s = 25
\n" ); document.write( "that makes a = 30 because a + s = 55\r
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\n" ); document.write( "\n" ); document.write( "30a + 40s becomes 30 * 30 + 40 * 25 = 900 + 1000 = 1900
\n" ); document.write( "this confirms the values of a and s are correct.\r
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\n" ); document.write( "\n" ); document.write( "the price of an advance ticket was 30 and the price of a same day ticket was 25.
\n" ); document.write( "that's your solution.
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