document.write( "Question 1189913: Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $55. For one performance, 30 advance tickets and 40 same-day tickets were sold. The total amount paid for the tickets was $1900. What was the price of each kind of ticket? \n" ); document.write( "
Algebra.Com's Answer #821415 by Theo(13342)![]() ![]() You can put this solution on YOUR website! a = number of advance tickets. \n" ); document.write( "s = number of same day tickiets.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "equations that need to be solved simultaneously are: \n" ); document.write( "a + s = 55 \n" ); document.write( "30a + 40s = 1900\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply both sides of the first equation by 30 and leave the second equatin as is to get: \n" ); document.write( "30a + 30s = 1650 \n" ); document.write( "30a + 40s = 1900\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract the first equation from the second to get: \n" ); document.write( "10s = 250 \n" ); document.write( "solve for s to get: \n" ); document.write( "s = 25 \n" ); document.write( "that makes a = 30 because a + s = 55\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "30a + 40s becomes 30 * 30 + 40 * 25 = 900 + 1000 = 1900 \n" ); document.write( "this confirms the values of a and s are correct.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the price of an advance ticket was 30 and the price of a same day ticket was 25. \n" ); document.write( "that's your solution. \n" ); document.write( " \n" ); document.write( " |