document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1189872>Question 1189872</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This question is really all about Distance and Midpoint Formula\r<BR>\n" );
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document.write( "You are going on a two-day hike. The map at the right shows the trails you plan to follow. (Each unit represents 1 mile.)\r<BR>\n" );
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document.write( "a. You hike from the lodge to point A and decide that you will hike to the midpoint of AB before you camp for the night. At what point in the plane will you be camping?\r<BR>\n" );
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document.write( "b. How far will you hike each day?\r<BR>\n" );
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document.write( "I think I can’t post the illustration but I hope opening this link would help https://mrrossatgradyhigh.files.wordpress.com/2016/08/10-1-distance-and-midpoint-formulas.pdf<BR>\n" );
document.write( "(Located 4th page of the pdf, question number 16)\r<BR>\n" );
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document.write( "Answering this question would help me a lot, thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #821378 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=821378\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The midpoint of AB has coordinate x which is the average of the two x components (-0.50) and the same for the two y components (4), so it is at (-0.5, 4).<BR>\n" );
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document.write( "first day is sqrt(13) distance because distance is sqrt(difference x^2+difference y^2). That is to A.<BR>\n" );
document.write( "Easier to do AB, and that distance is sqrt(5^2+4^2)=sqrt(41). Unlike slope, where which order you use the variable matters, it doesn't matter with distance, since you are squaring. You hike half of that the first day, so the total distance is sqrt(13)+(0.5)sqrt(41). That can be put into decimal form.<BR>\n" );
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document.write( "The total distance is sqrt(13)+sqrt(41)+ the last leg, which is sqrt(40). The distance the second day is <BR>\n" );
document.write( "0.5*sqrt(41)+ sqrt (40) </SPAN>\n" );
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