document.write( "Question 313761: Mr. Abbot left Farmersville in a plane at noon to travel to Exeter. Mr. Baker left Exeter in his automobile at 2pm to travel to Farmersville. It is 400 mi from Exeter to Farmersville. If the sum of their speeds was 120mph, and if they crossed paths at 4pm, find the speed of each.\r
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document.write( "x= speed of plane
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document.write( "y= speed if automobile\r
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document.write( "The system is
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document.write( "x+y=400
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document.write( "4x+4y=120 \n" );
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Algebra.Com's Answer #821356 by slitco(2)![]() ![]() You can put this solution on YOUR website! p = speed of plane \n" ); document.write( "a = speed of automobile \n" ); document.write( "------------------------ \n" ); document.write( "p + a = 120\r \n" ); document.write( "\n" ); document.write( "but were gonna make this \"a = -p + 120\" for the sake of the problem bc that's what works lol.\r \n" ); document.write( "\n" ); document.write( "then the other equation will be 4p + 2a = 400 \n" ); document.write( "------------------------------------------------------------------- \n" ); document.write( "4p + 2(-p + 120) = 400\r \n" ); document.write( "\n" ); document.write( "4p - 2p + 240 = 400\r \n" ); document.write( "\n" ); document.write( "2p + 240 = 400\r \n" ); document.write( "\n" ); document.write( "2p = 160\r \n" ); document.write( "\n" ); document.write( "p = 80 mph (plane)\r \n" ); document.write( "\n" ); document.write( "then plug 80 into -p in the other equation...which is a = -p + 120\r \n" ); document.write( "\n" ); document.write( "and that gives you...\r \n" ); document.write( "\n" ); document.write( "a = 40 mph (automobile) \r \n" ); document.write( "\n" ); document.write( ":) <3 \n" ); document.write( " |