document.write( "Question 1189850: Is this problem possible to solve?
\n" ); document.write( "I have tried applying the Pythagorean theorem, quadratic equations etc. but have been unable to come up with a solvable equation.\r
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\n" ); document.write( "\n" ); document.write( "The diagonal measure of a small TV screen is 1 inch greater than the length and 2 inches
\n" ); document.write( "greater than the width. Find the length and width\r
\n" ); document.write( "\n" ); document.write( "I would appreciate if anyone can point out something I am missing, or if this is a flawed problem. \n" ); document.write( "

Algebra.Com's Answer #821344 by ikleyn(52864) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "Let x be the diagonal length, in inches.\r\n" );
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document.write( "Then the legs are (x-1) inches and (x-2) inches.\r\n" );
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document.write( "Pythagorean equation\r\n" );
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document.write( "    x^2 = (x-1)^2 + (x-2)^2.\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    x^2 = x^2 - 2x + 1   +   x^2 - 4x + 4\r\n" );
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document.write( "    0   =     x^2 - 6x + 5\r\n" );
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document.write( "Factor\r\n" );
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document.write( "    (x-5)*(x-1)  = 0\r\n" );
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document.write( "The roots are 5 and 1;  but only 5 gives the solution to the problem.\r\n" );
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document.write( "So, the hypotenuse is 5 inches;  the legs are  5-1 = 4 inches and 5-2 = 3 inches.\r\n" );
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document.write( "The dimensions of the small TV screen are 3 inches by 4 inches.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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