document.write( "Question 1189846: A chemical company makes two brands of antifreeze. The first brand is 70% pure antifreeze, and the second brand is 95% pure antifreeze. In order to obtain 50
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document.write( "gallons of a mixture that contains 75% pure antifreeze, how many gallons of each brand of antifreeze must be used? \r
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document.write( "First brand ? Gallons
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document.write( "Second brand ? Gallons \n" );
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Algebra.Com's Answer #821336 by Theo(13342)![]() ![]() You can put this solution on YOUR website! let x = the amount of solution in the first brand. \n" ); document.write( "let y = the amount of solution in the second brand.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have two equations that need to be solved simultaneously. \n" ); document.write( "they are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + y = 50 \n" ); document.write( ".7 * x + .95 * y = .75 * 50\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply both sides of the first equation by .7 and lease the second equation as is to get: \n" ); document.write( ".7 * x + .7 * y = .7 * 50 \n" ); document.write( ".7 * x + .95 * y = .75 * 50\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify the right side of each equation to get: \n" ); document.write( ".7 * x + .7 * y = 35 \n" ); document.write( ".7 * x + .95 * y = 37.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract the first equation from the second to get: \n" ); document.write( ".25 * y = 2.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for y to get: \n" ); document.write( "y = 10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that means x = 40 because 40 + 10 = 50\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "confirm the solution is correct by replacing x with 40 and y with 10 in both original equations.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + y = 50 becomes 40 + 10 = 50 which becomes 50 = 50 \n" ); document.write( ".7 * x + .95 * y becomes .7 * 40 + .95 * 10 which becomes 28 + 9.5 which becomes 37.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this confirms the solution is correct. \n" ); document.write( "the solution is 40 gallons of the first brand and 10 gallons of the second brand is required.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |