document.write( "Question 1189793: It takes a smaller hose 4 times as long to fill a small swimming pool as it does a larger hose. It takes both hoses working together 20 minutes to fill the swimming pool. How long will it take the smaller hose to fill the pool by itself?
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Algebra.Com's Answer #821265 by josgarithmetic(39623) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "                 FILL RATE       TIME (minutes) for 1 POOL\r\n" );
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document.write( "Large Hose        1/x             x\r\n" );
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document.write( "Small Hose        1/(4x)          4x            \r\n" );
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document.write( "Combined        1/x+1/(4x)        20\r\n" );
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\n" ); document.write( " $\"1%2Fx%2B1%2F%284x%29=1%2F20\"$ \r
\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( " $\"5%2F%284x%29=1%2F20\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"4x%2F5=20\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=20%285%2F4%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"highlight_green%28x=25%29\"$ -------minutes for the large hose by itself.\r
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\n" ); document.write( "\n" ); document.write( " $\"25%2A4=highlight%28100%29\"$ ----------minutes for the small hose by itself. \n" ); document.write( "

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