document.write( "Question 1189731: While standing on a 75m tall bridge, given can see two boats. From his position on the bridge, the first boat is located on a bearing of 70 degrees and the second boat is located on a bearing of 300 degrees. Gavin estimates that the angles of depression for each of the boats are 38 degrees and 47 degrees respectively. How far apart are the boats?\r
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Algebra.Com's Answer #821225 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: 150.79 meters approximately\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=============================================== \n" ); document.write( "Explanation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Define these points
\n" ); document.write( "Realistically, the water is bobbing the boats around, so such an assumption isn't entirely valid (but again we'll make things relatively simple).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Due to the 3D nature of this problem, we'll have to break it down into 2D pieces.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "On a separate part of the paper, draw out right triangle ACD. This is a side profile view for the boat 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here are all the relevant drawings needed. \n" ); document.write( " ![]() \n" ); document.write( "For now, focus on triangle ACD only. \n" ); document.write( "That triangle has these sides \n" ); document.write( "CD = 75 meters = height \n" ); document.write( "AC = unknown\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the tangent ratio to get... \n" ); document.write( "tan(angle) = opposite/adjacent \n" ); document.write( "tan(A) = CD/AC \n" ); document.write( "tan(38) = 75/AC \n" ); document.write( "AC*tan(38) = 75 \n" ); document.write( "AC = 75/tan(38) \n" ); document.write( "AC = 95.99562 approximately \n" ); document.write( "Notice how angle A of triangle ACD is equal to the angle of depression for the first boat. \n" ); document.write( "This is due to the alternate interior angles theorem.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Through similar calculations for triangle BCD, you should find that BC = 75/tan(47) = 69.93863 meters approximately.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we'll consider the birds-eye-view to look directly down on triangle ABC. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We already found that \n" ); document.write( "AC = 95.99562 \n" ); document.write( "BC = 69.93863 \n" ); document.write( "which are sides b and 'a' in that order \n" ); document.write( "In other words, \n" ); document.write( "b = AC = 95.99562 \n" ); document.write( "a = BC = 69.93863\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The ultimate goal is to find the length of segment c = AB, which is the distance between the boats.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The bearings 70 and 300 have a gap of 300-70 = 230 degrees between them. \n" ); document.write( "The remaining bit is 360-230 = 130 degrees \n" ); document.write( "This measures angle ACB, aka angle C.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the law of cosines to find side c = AB \n" ); document.write( "c^2 = a^2+b^2-2*a*b*cos(C) \n" ); document.write( "c^2 = 69.93863^2+95.99562^2-2*69.93863*95.99562*cos(130) \n" ); document.write( "c^2 = 22,737.6687 \n" ); document.write( "c = sqrt(22,737.6687) \n" ); document.write( "c = 150.79 meters is the approximate distance between the two boats \n" ); document.write( " \n" ); document.write( " |