document.write( "Question 1189739: A laboratory test machine costs 150, 000, lasts for 6 years and has a salvage value of 30, 000. How much could an investor afford to pay for another
\n" ); document.write( "machine of the same purpose, whose life is 10 years with a salvage value of 40,000, if money is worth 5%.
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Algebra.Com's Answer #821217 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
i used the financial calculator at \r
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\n" ); document.write( "\n" ); document.write( "first i found out what the annual payment was for 150,000 at 5% for 6 years with a salvage value of 30,000.\r
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\n" ); document.write( "\n" ); document.write( "those results are shown below:\r
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\n" ); document.write( "\n" ); document.write( "i then found out what the present value was for 25142.10 annual payment at 5% for 8 years with a salvage value of 40,000.\r
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\n" ); document.write( "\n" ); document.write( "those result are shown below:\r
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\n" ); document.write( "\n" ); document.write( "the input for the first analysis was everything except pmt.
\n" ); document.write( "the output was pmt.\r
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\n" ); document.write( "\n" ); document.write( "the input for the second analysis was everything except present value.
\n" ); document.write( "the output was present value.\r
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\n" ); document.write( "\n" ); document.write( "this made both plans equivalent to each other in terms of the annual charges per year.\r
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\n" ); document.write( "\n" ); document.write( "the interpretation is that buying a piece of equipment for 189,572.32 with an economic life of 8 years and a salvage value of 40,000 is equivalent, in terms of annual charges, to buying a piece of equipment for 150,000 with an economic life of 6 years and a salvage value of 30,000.\r
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