document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=112635>Question 112635</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please show me step by step. \r<BR>\n" );
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document.write( "the Randolph's used 12 more gallons of fuel oil in October than in September and twice as much oil in November as in September. if they used 132 gallons for the 3 months, how much was used during each month?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82115 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82115\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Notice that the consumption of fuel oil for each of the months is based on the amount used<BR>\n" );
document.write( "in September.  So let's identify the unknown consumption in September as \"S\" gallons.<BR>\n" );
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document.write( "The October consumption was 12 gallons more than September. So the October consumption<BR>\n" );
document.write( "was S + 12 gallons.<BR>\n" );
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document.write( "The November consumption was twice that of September. So the November consumption was 2*S gallons.<BR>\n" );
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document.write( "The total consumption for the three months is the sum of these three amounts ... which is:<BR>\n" );
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document.write( "S + S + 12 + 2S<BR>\n" );
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document.write( "Adding up all the three terms that contain S gallons (that is S + S + 2S) results in <BR>\n" );
document.write( "the total consumption being:<BR>\n" );
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document.write( "4S + 12<BR>\n" );
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document.write( "But the problem tells you that this total consumption equals 132 gallons. So in equation form<BR>\n" );
document.write( "we can write:<BR>\n" );
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document.write( "4S + 12 = 132<BR>\n" );
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document.write( "Get rid of the 12 on the left side by subtracting 12 from both sides of this equation to get:<BR>\n" );
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document.write( "4S = 120<BR>\n" );
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document.write( "Solve for S by dividing both sides by 4:<BR>\n" );
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document.write( "S = 120/4 = 30 gallons<BR>\n" );
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document.write( "If 30 gallons was consumed in September, the October consumption was 12 gallons more,<BR>\n" );
document.write( "so it was 42 gallons. And the November consumption was 2 times that of September so<BR>\n" );
document.write( "it was 30 times 2 = 60 gallons.<BR>\n" );
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document.write( "This means the total consumption was 30 + 42 + 60 and this adds up to 132 gallons,<BR>\n" );
document.write( "just as the problem said it should.<BR>\n" );
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document.write( "The answer to this problem is:<BR>\n" );
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document.write( "September = 30 gallons<BR>\n" );
document.write( "October = 42 gallons<BR>\n" );
document.write( "November = 60 gallons<BR>\n" );
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document.write( "Hope this helps you to understand the problem.<BR>\n" );
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