document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1189689>Question 1189689</A>: <I><SPAN STYLE=\"word-break: break-all;\"> pure acid is to be added to a 10% acid solution to obtain a 24 L OK 40% acid solution. What amount should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #821129 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=821129\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  pure acid is to be added to a 10% acid solution to obtain a 24 L OK 40% acid solution.<BR>\n" );
document.write( " What amount should be used? <BR>\n" );
document.write( ":<BR>\n" );
document.write( "let a = amt of pure acid required to accomplish this<BR>\n" );
document.write( "The total amt is to be 24 L, therefore<BR>\n" );
document.write( "(24-a) = amt of 10% acid required<BR>\n" );
document.write( ":<BR>\n" );
document.write( "using the decimal equiv of per cent<BR>\n" );
document.write( "1a + .10(24-a) = .40(24)<BR>\n" );
document.write( "a + 2.4 - .10a = 9.6<BR>\n" );
document.write( "a - .10a = 9.6 - 2.4<BR>\n" );
document.write( ".9a = 7.2<BR>\n" );
document.write( "a = 7.2/.9<BR>\n" );
document.write( "a = 8 liters of pure acid required </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );