document.write( "Question 1189682: A ship sees a lighthouse which is found to be 9.8 km distant through the use of radar. The lighthouse is 3km from a second lighthouse. The angle between the line of sight between the two lighthouses is 30°. What is the angle between the line of sight between the ship and lighthouse 2, when looking from lighthouse 1? \n" ); document.write( "
Algebra.Com's Answer #821111 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Drawing \n" ); document.write( " ![]() \n" ); document.write( "A = ship's location \n" ); document.write( "B = lighthouse 1 \n" ); document.write( "C = lighthouse 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Angle A = 30 degrees \n" ); document.write( "Angle B = x degrees \n" ); document.write( "Angle C = 180-A-B = 180-30-x = 150-x degrees\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Apply the law of sines to find x \n" ); document.write( "sin(A)/a = sin(C)/c \n" ); document.write( "sin(30)/3 = sin(150-x)/9.8 \n" ); document.write( "0.5/3 = sin(150-x)/9.8 \n" ); document.write( "0.5*9.8 = 3sin(150-x) \n" ); document.write( "4.9 = 3sin(150-x) \n" ); document.write( "3*sin(150-x) = 4.9 \n" ); document.write( "sin(150-x) = 1.633333 approximately\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We run into a problem. Recall that \n" ); document.write( "So it's impossible to have sin(150-x) be 1.63 as that's larger than 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "No triangle is possible with those specified side lengths and angle. \n" ); document.write( "Please contact your teacher for clarification. \n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |