document.write( "Question 1189682: A ship sees a lighthouse which is found to be 9.8 km distant through the use of radar. The lighthouse is 3km from a second lighthouse. The angle between the line of sight between the two lighthouses is 30°. What is the angle between the line of sight between the ship and lighthouse 2, when looking from lighthouse 1? \n" ); document.write( "
Algebra.Com's Answer #821111 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Drawing
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\n" ); document.write( "A = ship's location
\n" ); document.write( "B = lighthouse 1
\n" ); document.write( "C = lighthouse 2\r
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\n" ); document.write( "\n" ); document.write( "Angle A = 30 degrees
\n" ); document.write( "Angle B = x degrees
\n" ); document.write( "Angle C = 180-A-B = 180-30-x = 150-x degrees\r
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\n" ); document.write( "\n" ); document.write( "Apply the law of sines to find x
\n" ); document.write( "sin(A)/a = sin(C)/c
\n" ); document.write( "sin(30)/3 = sin(150-x)/9.8
\n" ); document.write( "0.5/3 = sin(150-x)/9.8
\n" ); document.write( "0.5*9.8 = 3sin(150-x)
\n" ); document.write( "4.9 = 3sin(150-x)
\n" ); document.write( "3*sin(150-x) = 4.9
\n" ); document.write( "sin(150-x) = 1.633333 approximately\r
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\n" ); document.write( "\n" ); document.write( "We run into a problem. Recall that \"-1+%3C=+sin%28x%29+%3C=+1\", i.e. the outputs of sine are restricted to the interval between -1 and 1.
\n" ); document.write( "So it's impossible to have sin(150-x) be 1.63 as that's larger than 1.\r
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\n" ); document.write( "\n" ); document.write( "No triangle is possible with those specified side lengths and angle.
\n" ); document.write( "Please contact your teacher for clarification.
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