document.write( "Question 1189661: The derivative of f(x)=1/sqrt(2x-3), with x>3/2 is \n" ); document.write( "

Algebra.Com's Answer #821087 by MathLover1(20850) $\"\"$ $\"About$

You can put this solution on YOUR website!
The derivative of \r
\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=1%2Fsqrt%282x-3%29+\"$ \r
\n" ); document.write( "\n" ); document.write( "is\r
\n" ); document.write( "\n" ); document.write( " $\"%28d%2Fdx%29%281%2Fsqrt%282x-3%29+%29\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "= $\"%28d%2Fdx%29%28sqrt%282x-3%29+%5E%28-1%2F2%29%29\"$ ........apply chain rule\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "= $\"-%281%2F%282%282x-3%29%5E%283%2F2%29%29%29%28d%2Fdx%29%282x-3%29\"$ ......... $\"%28d%2Fdx%29%282x-3%29=2\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "= $\"-2%2F%282%282x-3%29%5E%283%2F2%29%29\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "= $\"-1%2F%282x-3%29%5E%283%2F2%29\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"f\"$ ' $\"%28x%29=-1%2F%28%282x-3%29%5E%283%2F2%29%29\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "domain: { $\"x\"$ element $\"R\"$ : $\"x%3E3%2F2\"$ }\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );