document.write( "Question 1189652: Hi, any chance I could get some help with this question?\r
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Algebra.Com's Answer #821077 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
table of values is:\r
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document.write( "time(days)           remaining amount of sucralose(mg)\r\n" );
document.write( "0                             40\r\n" );
document.write( "2                             20\r\n" );
document.write( "4                             10\r\n" );
document.write( "6                             5\r\n" );
document.write( "8                             2.5\r\n" );
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\n" ); document.write( "\n" ); document.write( "formula is y = a * b^x
\n" ); document.write( "a is the initial value.
\n" ); document.write( "b is the base for the exponent.
\n" ); document.write( "x is the exponent.\r
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\n" ); document.write( "\n" ); document.write( "from the table, you get 40 = 40 * b^0.
\n" ); document.write( "since b^0 is always equal to 1, you get 40 = 40 and b is still undefined.\r
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\n" ); document.write( "\n" ); document.write( "from the table, you get 20 = 40 * b^2.
\n" ); document.write( "solve for b^2 to get:
\n" ); document.write( "b^2 = .5
\n" ); document.write( "solve for b to get:
\n" ); document.write( "b = .7071067812.\r
\n" ); document.write( "\n" ); document.write( "from the table, you get 10 = 40 * b^4.
\n" ); document.write( "solve for b^4 to get:
\n" ); document.write( "b^4 = .25
\n" ); document.write( "solve for b to get:
\n" ); document.write( "b = .25^(1/4) = .7071067812.\r
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\n" ); document.write( "\n" ); document.write( "from the table, you get 5 = 40 * b^6.
\n" ); document.write( "solve for b^6 to get:
\n" ); document.write( "b^6 = 1/8
\n" ); document.write( "solve for b to get:
\n" ); document.write( "b = (1/8)^(1/6) = .7071067812.\r
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\n" ); document.write( "\n" ); document.write( "this very much indicates that b = .7071067812.\r
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\n" ); document.write( "\n" ); document.write( "your formula is y = 40 * (.7071067812) ^ x\r
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\n" ); document.write( "\n" ); document.write( "note that sqrt(.5) = .7071067812.\r
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\n" ); document.write( "\n" ); document.write( "you can graph this formula.
\n" ); document.write( "it looks like this:\r
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\n" ); document.write( "\n" ); document.write( "your unrounded formula is:\r
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\n" ); document.write( "\n" ); document.write( "y = 40 * .7071067812 ^ x\r
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\n" ); document.write( "\n" ); document.write( "your rounded formula is:\r
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\n" ); document.write( "\n" ); document.write( "y = 40 * .71 ^ x\r
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\n" ); document.write( "\n" ); document.write( "your rate of decay is 50% every 2 days.\r
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\n" ); document.write( "\n" ); document.write( "every day, the amount of sucralose in the body is .7071067812 times the amount in the previous day.\r
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\n" ); document.write( "\n" ); document.write( "that's a loss of (1 - .7071067812) = .2928932188 * the amount of sucralose from the previous day.\r
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\n" ); document.write( "\n" ); document.write( "on day 0 you have 40.
\n" ); document.write( "on day 1 you have .7071067812 * 40 = 28.28427125.
\n" ); document.write( "that's a loss of 40 - 28.28427125 = 11.71572875 sucralos.
\n" ); document.write( "that is 11.71572875 / 40 = a loss of .2928932188 = 29.28932188%.\r
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\n" ); document.write( "\n" ); document.write( "the rounded rate of decay formula is:
\n" ); document.write( "y = 40 * .71 ^ x
\n" ); document.write( "every day, you have .71 * the amount of sucralose in your body that you had the previous day.\r
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\n" ); document.write( "\n" ); document.write( "let me know if you have any questions.\r
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\n" ); document.write( "\n" ); document.write( "theo
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