document.write( "Question 1189629: Find the value of (f ∘ g)′ at the given value of x.\r
\n" ); document.write( "\n" ); document.write( "f(u)= u/ ((u^2)-1) ,u=g(x)=(6x^2)+x+4, x=0
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Algebra.Com's Answer #821053 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "\"f%28u%29=+u%2F+%28u%5E2-1%29+\"
\n" ); document.write( "\"u=g%28x%29=6x%5E2%2Bx%2B4\"
\n" ); document.write( "\"x=0\"\r
\n" ); document.write( "\n" ); document.write( "Find: the value of (f ∘ g)′ at the given value of \"x\".\r
\n" ); document.write( "\n" ); document.write( "(f ∘ g)′ =\"f%28g%28x%29%29\"\r
\n" ); document.write( "\n" ); document.write( "(f ∘ g)′ =\"f%286x%5E2%2Bx%2B4%29\"\r
\n" ); document.write( "\n" ); document.write( "(f ∘ g)′ =\"%286x%5E2%2Bx%2B4%29%2F%28%286x%5E2%2Bx%2B4%29%5E2-1%29\"\r
\n" ); document.write( "\n" ); document.write( "(f ∘ g)′ =\"%286x%5E2%2Bx%2B4%29%2F%28%286+x%5E2+%2B+x+%2B+3%29+%286+x%5E2+%2B+x+%2B+5%29%29\"\r
\n" ); document.write( "\n" ); document.write( "substitute \"x=0\"\r
\n" ); document.write( "\n" ); document.write( "(f ∘ g)′\r
\n" ); document.write( "\n" ); document.write( "(f ∘ g)′\"%280%29+=4%2F%28+3%2A+5%29\"\r
\n" ); document.write( "\n" ); document.write( "(f ∘ g)′\"%280%29+=4%2F15\"\r
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