document.write( "Question 1189627: Find the derivative of y with respect to x.\r
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Algebra.Com's Answer #821052 by MathLover1(20850)\"\" \"About 
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given:\r
\n" ); document.write( "\n" ); document.write( "\"y=ln%28ln+%282x%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Find the derivative of \"y\" with respect to \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28d%2Fdx%29%28ln%28ln%282x%29%29%29\"..........apply chain rule\r
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\n" ); document.write( "\n" ); document.write( "=\"%281%2Fln%282x%29%29%28d%2Fdx%29%28ln%282x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "so, \"%28d%2Fdx%29%28ln+%282x%29%29=1%2Fx\", and we have\r
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\n" ); document.write( "\n" ); document.write( "=\"%281%2Fln%282x%29%29%281%2Fx%29\"............simplify\r
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\n" ); document.write( "\n" ); document.write( "=\"1%2F%28x%2Aln%282x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "answer: \"y\"'\"%28x%29+=+1%2F%28x%2Alog%282+x%29%29\"\r
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