document.write( "Question 1189628: If a Php 25,000 investment receives 5% interest each year, after how many years will the investment have doubled in value \n" ); document.write( "
Algebra.Com's Answer #821049 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "We use this compound interest formula \n" ); document.write( "A = P*(1+r/n)^(n*t) \n" ); document.write( "In this case, \n" ); document.write( "A = 50,000 = because we wish to double the deposit amount P \n" ); document.write( "P = 25,000 = principal or deposit amount \n" ); document.write( "r = 0.05 = interest rate in decimal form \n" ); document.write( "n = 1 = since we're compounding annually \n" ); document.write( "t = unknown\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, \n" ); document.write( "A = P*(1+r/n)^(n*t) \n" ); document.write( "50000 = 25000*(1+0.05/1)^(1*t) \n" ); document.write( "50000/25000 = (1.05)^t \n" ); document.write( "2 = (1.05)^t \n" ); document.write( "Ln(2) = Ln( (1.05)^t ) \n" ); document.write( "Ln(2) = t*Ln( 1.05 ) \n" ); document.write( "t = Ln(2)/Ln(1.05) \n" ); document.write( "t = 14.206699 approximately \n" ); document.write( "t = 15 years\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It takes approximately 15 years for the money to double.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note the rule of 72 says \n" ); document.write( "72/5 = 14.4 \n" ); document.write( "which is fairly close to the 14.206699 value we got earlier. \n" ); document.write( "To use this rule, we simply divide the value 72 over the numeric form of the interest rate. We treat the \"5\" as is without the percent sign. \n" ); document.write( "For more info, check out this page \n" ); document.write( "https://www.basic-mathematics.com/why-the-rule-of-72-works.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Other things to notice \n" ); document.write( "A(t) = 25000(1.05)^t \n" ); document.write( "A(14) = 49,498.29 \n" ); document.write( "A(15) = 51,973.20 \n" ); document.write( "which helps confirm that 14 years is just a bit shy of the goal of Php 50,000; while 15 years will get you over the hurdle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Once again, the final answer is approximately 15 years \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |