document.write( "Question 1189616: If 8 percent of an 18-gallon solution is chlorine, how many gallons of water must be added to make a new solution that is 6 percent chlorine?
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Algebra.Com's Answer #821027 by ikleyn(52794)\"\" \"About 
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\n" ); document.write( "If 8 percent of an 18-gallon solution is chlorine, how many gallons of water must be added
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document.write( "The amount of chlorine is the same (remains the same) in the original mixture and after diluting.\r\n" );
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document.write( "So, if W is the volume of water to add, we have this equation for the chlorine mass\r\n" );
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document.write( "    0.08*18 = 0.06*(18+W).\r\n" );
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document.write( "From this equation\r\n" );
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document.write( "    0.08*18 = 0.06*18 + 0.06*W\r\n" );
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document.write( "    0.08*18 - 0.06*18 = 0.06W\r\n" );
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document.write( "        0.02*18       = 0.06W\r\n" );
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document.write( "        W = \"%280.02%2A18%29%2F0.06\" = \"18%2F3\" = 6  gallons.    ANSWER\r\n" );
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