document.write( "Question 1189574: Use implicit differentiation to find the equation of the tangent line at the given point\r
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Algebra.Com's Answer #821012 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"arctan%28x%2By%29=y%5E2%2Bpi%2F4\"  @ (1,0)\r\n" );
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document.write( "We need the formula:  \"d%2Fdx\"\"arctan%28u%29\"\"%22%22=%22%22\"\"%28du%2Fdx%29%2F%281%2Bu%5E2%29\"\r\n" );
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document.write( "Let \"u+=+x%2By\", then \"du%2Fdx+=+1%2Bdy%2Fdx\".  For the right side,\r\n" );
document.write( "\"pi%2F4\" is just a constant and its derivative is 0.\r\n" );
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document.write( "\"%281%2Bdy%2Fdx%29%2F%281%2B%28x%2By%29%5E2%29\"\"%22%22=%22%22\"\"2y%2Aexpr%28dy%2Fdx%29\"\r\n" );
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document.write( "Now we substitute x=1 and y=0, then solve for \"dy%2Fdx\"\r\n" );
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document.write( "\"%281%2Bdy%2Fdx%29%2F%281%2B%281%2B0%29%5E2%29\"\"%22%22=%22%22\"\"2%280%29%2Aexpr%28dy%2Fdx%29\"\r\n" );
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document.write( "\"%281%2Bdy%2Fdx%29%2F%281%2B%281%29%5E2%29\"\"%22%22=%22%22\"\"0\"\r\n" );
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document.write( "\"%281%2Bdy%2Fdx%29%2F%281%2B1%29\"\"%22%22=%22%22\"\"0\"\r\n" );
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document.write( "\"%281%2Bdy%2Fdx%29%2F%282%29\"\"%22%22=%22%22\"\"0\"\r\n" );
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document.write( "\"1%2Bdy%2Fdx\"\"%22%22=%22%22\"\"0\"\r\n" );
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document.write( "\"dy%2Fdx\"\"%22%22=%22%22\"\"-1\"     \r\n" );
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document.write( "That's the slope of the tangent line\r\n" );
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document.write( "Now find the equation of the tangent line which goes thru\r\n" );
document.write( "(1,0), which has the slope m = -1\r\n" );
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document.write( "\"y-0\"\"%22%22=%22%22\"\"-1%28x-1%29\"\r\n" );
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document.write( "\"y\"\"%22%22=%22%22\"\"-x%2B1\"\r\n" );
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document.write( "Edwin
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