document.write( "Question 16709: Traceling downstream, a boat covers a distance of 27 kilometers in 3 hrs. Traveling upstream it taks the boat twice at mush time to cover 2/3s of the dist. Find the reat of the boat in still water and the rate of the current. \n" ); document.write( "

Algebra.Com's Answer #8210 by xcentaur(357) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let the speed of the boat be x and the speed of the current downstream be y\r
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "then x+y=27/3=9 km/hr [speed downstream]\r\n" );
document.write( "\r\n" );
document.write( "then x-y=(2/3*27)/6 [two thirds of distance means 2/3 of 27 km.]\r\n" );
document.write( "                   
 [double the time means 6 hours instead of 3]\r\n" );
document.write( "\r\n" );
document.write( "=2*(18)/6= 6 km/hr [speed upstream]\r\n" );
document.write( "\r\n" );
document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "now x+y=9\r\n" );
document.write( "    x-y=6\r\n" );
document.write( "\r\n" );
document.write( "2x=15 => x=7.5 km/hr [solving simueltanously]\r\n" );
document.write( "\r\n" );
document.write( "then y=9-x=9-7.5=1.5 km/hr\r\n" );
document.write( "

\n" ); document.write( "

\n" ); document.write( "Hence,speed of boat in still water will be 7.5 km/hr and rate of current is 1.5 km/hr.\r
\n" ); document.write( "\n" ); document.write( "Hope this helps,
\n" ); document.write( "Prabhat \n" ); document.write( "

\n" );