document.write( "Question 112586: The length of a rectangle is 5 more than twice the width. The perimeter is 130. What is the area? \n" ); document.write( "
Algebra.Com's Answer #82099 by checkley71(8403)\"\" \"About 
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L=2W+5
\n" ); document.write( "PERIMETER=2L+2W
\n" ); document.write( "130=2(2W+5)+2W
\n" ); document.write( "130=4W+10+2W
\n" ); document.write( "130=6W+10
\n" ); document.write( "6W=130-10
\n" ); document.write( "6W=120
\n" ); document.write( "W=120/6
\n" ); document.write( "W=20 ANSWER FOR THE WIDTH.
\n" ); document.write( "L=2*20+5
\n" ); document.write( "L=40+5
\n" ); document.write( "L=45
\n" ); document.write( "PROOF
\n" ); document.write( "2*45+2*20=130
\n" ); document.write( "90+40=130
\n" ); document.write( "130=130
\n" ); document.write( "
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