document.write( "Question 1189586: A solution of water and alcohol is 25% alcohol. If the amount of water is doubled what percent is now alcohol? \n" ); document.write( "
Algebra.Com's Answer #820989 by Theo(13342)\"\" \"About 
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the way i see this problem is as follows:\r
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\n" ); document.write( "\n" ); document.write( "you have a solution of water and alcohol.
\n" ); document.write( "the solution is 3 parts water and 1 part alcohol.
\n" ); document.write( "the percent of alcohol is 1/4 = .25 = 25%.\r
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\n" ); document.write( "\n" ); document.write( "if you double the water, they you are adding another 3 parts of water to get:\r
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\n" ); document.write( "\n" ); document.write( "6 parts water and 1 part alcohol.
\n" ); document.write( "the percent of alcohol is 1/7 = .1428571429 = 14.28571429%.\r
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\n" ); document.write( "\n" ); document.write( "as a test, i assumed 100 liters of solution that is 75% water and 25% alcohol.
\n" ); document.write( "that divides into 3 parts water and 1 part alcohol.
\n" ); document.write( "that means 75 liters water and 25 liters alcohol.
\n" ); document.write( "i doubled the amount of water to get 150 liters water and 25 liters alcohol in a total solution of 175 liters.
\n" ); document.write( "the percent alcohol became 25/175 = .1428571429 = 14.28571429%.\r
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\n" ); document.write( "\n" ); document.write( "method looks good.
\n" ); document.write( "solution is 14.29% alcohol rounded to 2 decimal places.
\n" ); document.write( "round your number as required.
\n" ); document.write( "the detailed solution is 14.28571429% alcohol.\r
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