document.write( "Question 112596: Hello, I have been working on this problem all day and it seems the more I work on it the more confusing I seem to make it for myself. I over think too much if that is even possible Here is the problem: There are 850 Douglas fir and ponderosa pine trees in a section of forest bought by Sawz Logging Co. The company paid an average of $300 for each Douglas fir and $225 for each ponderosa pine. If the company paid $217,500 for the trees, how many of each kind did the company buy?
\n" );
document.write( "I would really appreciate your help here I'm sure its so simple but I'm just not getting it.\r
\n" );
document.write( "\n" );
document.write( "Thank You, Barbara Neely \n" );
document.write( "
Algebra.Com's Answer #82097 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! D+P=850 or D=850-P NOW SUBSTITUTE (850-P) FOR D IN THE FOLLOWING EQUATION & SOLVE FOR P \n" ); document.write( "300D+225P=217,500 \n" ); document.write( "300(850-P)+225P=217,500 \n" ); document.write( "255,000-300P+225P=217,500 [THE 255,000 IS THE PRODUCT OF (300*850)] \n" ); document.write( "-75P=217,500-255,000 \n" ); document.write( "-75P=-37,500 \n" ); document.write( "P=-37,500/-75 \n" ); document.write( "P=500 IS THE NUMBER OF PONDEROSA PINES BOUGHT. \n" ); document.write( "850-500=350 IS THE NUMBER OF DOUGLAS FIRS BOUGHT. \n" ); document.write( "PROOF \n" ); document.write( "300*350+225*500=217,500 \n" ); document.write( "105,000+112,500=217,500 \n" ); document.write( "217,500=217,500 \n" ); document.write( " |