document.write( "Question 1189539: A person leaves their work and heads home 5km away. They walk at 5km/h during the start but then it starts to rain so they run the rest of the way at 12km/h. They leave at 5:30pm and arrives home at 6:09 pm. Create a system of equations. How far did the person run for? How long did the person walk for? \n" ); document.write( "

Algebra.Com's Answer #820923 by ikleyn(52802) $\"\"$ $\"About$

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\n" ); document.write( "A person leaves their work and heads home 5km away.
\n" ); document.write( "They walk at 5km/h during the start but then it starts to rain
\n" ); document.write( "so they run the rest of the way at 12km/h.
\n" ); document.write( "They leave at 5:30pm and arrives home at 6:09 pm.
\n" ); document.write( "Create a system of equations.
\n" ); document.write( "How far did the person run for? How long did the person walk for?
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document.write( "Let x be the distance the person ran, in kilometers.\r\n" );
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document.write( "Then the distance he walked was (5-x) kilometers.\r\n" );
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document.write( "Now write the \"time equation\"\r\n" );
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document.write( "    time to walk + time to run = 39 minutes, or  of an hour\r\n" );
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document.write( "          +          = .\r\n" );
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document.write( "To solve it, multiply both sides by 5*12 = 60.  You will get\r\n" );
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document.write( "    12*(5-x) + 5x = 39\r\n" );
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document.write( "    60 - 12x + 5x = 39\r\n" );
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document.write( "    60 - 39 = 7x\r\n" );
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document.write( "      21    = 7x\r\n" );
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document.write( "       x    = 21/7 = 3.\r\n" );
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document.write( "ANSWER.  3 kilometer running and (5-3) = 2 kilometers walking.\r\n" );
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