document.write( "Question 1189536: A motorboat travels 343 kilometers in 7 hours going upstream and 819 kilometers in 9 hours going downstream. What is the rate of the boat in still water and what is the rate of the current? \n" ); document.write( "
Algebra.Com's Answer #820912 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "b = speed of the boat in still water
\n" ); document.write( "c = speed of the current\r
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\n" ); document.write( "\n" ); document.write( "When the boat goes upstream, the current slows the boat down to a speed of b-c\r
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\n" ); document.write( "\n" ); document.write( "For the upstream data, we'll plug in the given distance and time to solve for b
\n" ); document.write( "distance = rate*time
\n" ); document.write( "343 = (b-c)*7
\n" ); document.write( "343/7 = b-c
\n" ); document.write( "49 = b-c
\n" ); document.write( "49+c = b
\n" ); document.write( "b = 49+c\r
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\n" ); document.write( "\n" ); document.write( "When the boat goes downstream, the current speeds up the boat to a speed of b+c\r
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\n" ); document.write( "\n" ); document.write( "Plug in the distance and time pertaining to the downstream scenario, along with b = 49+c, to solve for c.\r
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\n" ); document.write( "\n" ); document.write( "Distance = rate*time
\n" ); document.write( "819 = (b+c)*9
\n" ); document.write( "819 = (49+c+c)*9
\n" ); document.write( "819 = (49+2c)*9
\n" ); document.write( "819/9 = 49+2c
\n" ); document.write( "91 = 49+2c
\n" ); document.write( "2c+49 = 91
\n" ); document.write( "2c = 91-49
\n" ); document.write( "2c = 42
\n" ); document.write( "c = 42/2
\n" ); document.write( "c = 21
\n" ); document.write( "The speed of the current is 21 km per hour.
\n" ); document.write( "b = 49+c
\n" ); document.write( "b = 49+21
\n" ); document.write( "b = 70
\n" ); document.write( "The boat's speed in still water is 70 km per hour.
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