document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=112566>Question 112566</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you tell me how to do this\r<BR>\n" );
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document.write( "5.	Fill in the chart given this linear equation:<BR>\n" );
document.write( "3x + y =10<BR>\n" );
document.write( "x	   	           y=	            	           	      <BR>\n" );
document.write( "-2<BR>\n" );
document.write( "-1<BR>\n" );
document.write( "0<BR>\n" );
document.write( "1<BR>\n" );
document.write( "2\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82091 by </B><A HREF=/tutors/aboutme.mpl?userid=ilana><B>ilana(307)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ilana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82091\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, write the equation in terms of y.  y = 10-3x, or y = -3x + 10.<BR>\n" );
document.write( "Now substitute each x.  When x=-2, y = 10 - 3*(-2), so y = 10 - (-6), or y=10+6, so y=16.  Substitute each value of x to complete the chart. </SPAN>\n" );
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