document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=112547>Question 112547</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The gas guage on the van initially read 1/8 full.  When 15 gallons were added to the tank the guage read 3/4 full.   How many more gallons are needed to fill the tank?  I know the answer is 6 but I can't get an equation to prove it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82081 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82081\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=number of additional gallons needed to fill the tank\r<BR>\n" );
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document.write( "The 15 gal alone that were added filled the tank to (3/4-1/8) or 5/8 capacity.  Since the tank was already 1/8 full, only 1/4 now remains to be filled.  So we have the following ratio:<BR>\n" );
document.write( "15 is to 5/8 as x is to 1/4 or 2/8<BR>\n" );
document.write( "15/(5/8)=x/(2/8)  cross multiply\r<BR>\n" );
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document.write( "15(2/8)=(5/8)x  multiply both sides by 8\r<BR>\n" );
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document.write( "30=5x divide both sides by 5\r<BR>\n" );
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document.write( "x=6 gal\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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