document.write( "Question 1189428: log2 (3x + 1) + log8 (x - 1) ^ 2 = 6\r
\n" ); document.write( "\n" ); document.write( "Show that log8 (x - 1) ^ 2 = 6Hence solve the equation for underline x>0
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Algebra.Com's Answer #820808 by greenestamps(13203)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Unclear...!

\n" ); document.write( "What does this mean: \"solve the equation for underline x>0\"?

\n" ); document.write( "Furthermore, the given information appears to be inconsistent, so it is probably shown incorrectly.

\n" ); document.write( "Given

\n" ); document.write( "log2 (3x + 1) + log8 (x - 1) ^ 2 = 6,

\n" ); document.write( "if in fact (as you say we are supposed to show)

\n" ); document.write( "log8 (x - 1) ^ 2 = 6

\n" ); document.write( "then

\n" ); document.write( "log2 (3x + 1) = 0

\n" ); document.write( "which makes 3x+1=1, which means x=0; and then log8 (x - 1) ^ 2 is NOT equal to 6.

\n" ); document.write( "Re-post, showing the information correctly, and making it clear what the last part of the problem is.

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