document.write( "Question 1189444: The sum of all integral values of x for which (18(x^2 - 7x + 10)/x^3 - 6x^2 + 3x + 10) has an integral value is\r
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document.write( "A) -17
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document.write( "B) -19
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document.write( "C) -12
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document.write( "D) -14
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document.write( "E) -20 \n" );
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Algebra.Com's Answer #820803 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Your parentheses are in the wrong places. \n" ); document.write( "But at least, unlike a large number of people who submit questions to this forum, you TRIED to use parentheses.... \n" ); document.write( "Here is the expression you posted: (18(x^2 - 7x + 10)/x^3 - 6x^2 + 3x + 10) = \n" ); document.write( "Undoubtedly the expression you intended to show is this: 18(x^2 - 7x + 10)/(x^3 - 6x^2 + 3x + 10) = \n" ); document.write( "Factor the numerator and denominator and try to simplify the expression. \n" ); document.write( "The numerator factors easily.... \n" ); document.write( " \n" ); document.write( "There are many formal ways to factor the cubic polynomial in the denominator. However, since we are hoping the expression will simplify, let's check specifically to see if (x-5) and/or (x-2) are factors of the denominator. \n" ); document.write( "In fact they are both factors; the expression simplifies to \n" ); document.write( " \n" ); document.write( "The function is undefined for values that make the denominator 0: 5, 2, and -1. \n" ); document.write( "In this problem, we are not concerned with where the function is undefined; we are interested in the values of x that make the expression have an integer value. So we can cancel the common factors in the numerator and denominator to simplify the expression to \n" ); document.write( " \n" ); document.write( "That expression will have an integer value whenever (x+1) is a (positive or negative) factor of 18. We can simply make a list: \r\n" ); document.write( " x+1 x\r\n" ); document.write( " --------\r\n" ); document.write( " 18 17\r\n" ); document.write( " 9 8\r\n" ); document.write( " 6 5\r\n" ); document.write( " 3 2\r\n" ); document.write( " 2 1\r\n" ); document.write( " 1 0\r\n" ); document.write( " -1 -2\r\n" ); document.write( " -2 -3\r\n" ); document.write( " -3 -4\r\n" ); document.write( " -6 -7\r\n" ); document.write( " -9 -10\r\n" ); document.write( " -18 -19 \n" ); document.write( "Adding the values of x in the second column gives us a total of -12. \n" ); document.write( "ANSWER: C) -12 \n" ); document.write( " \n" ); document.write( " |