document.write( "Question 1189410: If sin theta=5/12, determine sin2theta, where theta is in the first quadrant. \n" ); document.write( "
Algebra.Com's Answer #820772 by ikleyn(52839)\"\" \"About 
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\n" ); document.write( "If sin theta=5/12, determine sin2theta, where theta is in the first quadrant.
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document.write( "Use the basic formula of Trigonometry\r\n" );
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document.write( "    \"sin%282theta%29\" = \"2sin%28theta%29%2Acos%28theta%29\".\r\n" );
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document.write( "From this formula, you see that you need to know \"cos%28theta%29\".\r\n" );
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document.write( "It is easy to calculate  \"cos%28theta%29\"  from  \"sin%28theta%29\"\r\n" );
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document.write( "    \"cos%28theta%29\" = \"sqrt%281-sin%5E2%28theta%29%29\" = \"sqrt%281+-+%285%2F12%29%5E2%29\" = \"sqrt%281-25%2F144%29\" = \"sqrt%28%28144-25%29%2F144%29\" = \"sqrt%28119%2F144%29\" = \"sqrt%28119%29%2F12\".\r\n" );
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document.write( "In the first quadrant, cosine is positive; therefore, we keep the positive sign of the square root.\r\n" );
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document.write( "Now  \"sin%282theta%29\" = \"2sin%28theta%29%2Acos%28theta%29\" = \"2%2A%285%2F12%29%2A%28sqrt%28119%29%2F12%29\" = \"%2810%2F144%29%2Asqrt%28119%29\" = 0.757549...   ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "P.S.   My inner voice tells me that should be   \"sin%28theta%29\" = \"5%2F13\"   in your post,  instead of  \"5%2F12\".\r
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\n" ); document.write( "\n" ); document.write( "If it is so,  do everything the same.  In this case the answer is   \"sin%282theta%29\" = \"2%2A%285%2F13%29%2A%2812%2F13%29\" = \"120%2F169\".\r
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