document.write( "Question 1189395: Please help me solve this problem!!\r
\n" ); document.write( "\n" ); document.write( ": A book dealer has books in store of which 1/5 were hardcover books . the dealer sold 2/3 of the books , including 3/4 of the hardcover books . what fraction of the unsold books were hardcover books??
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Algebra.Com's Answer #820766 by Octo-pie7(11)\"\" \"About 
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Assumption : Let z = 120 be the
\n" ); document.write( "totallity of all the books:
\n" ); document.write( "1/5(120) = 24 => no. of hardcover books
\n" ); document.write( "4/5(120) = 96 => no. of softcover books
\n" ); document.write( "2/3(120) = 80 => sold books, in w/c
\n" ); document.write( "3/4(24) = 18 are hardcover books
\n" ); document.write( " of remaining hardcover books:
\n" ); document.write( "x = 24 - 18 = 6
\n" ); document.write( "of remaining books :
\n" ); document.write( "y - 120 - 80 = 40
\n" ); document.write( "let r be the fractional part of
\n" ); document.write( "unsold books:
\n" ); document.write( "r = 6/40 = 3/20
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