document.write( "Question 1189399: When the digits in the number 2005 are reversed we obtain the number 5002, and 5002 = a * b * c, such that a, b and c are three distinct primes. How many other positive integers are the products of exactly three distinct primes prime1, prime2 and prime3 such that prime1 + prime2 + prime3 = a+b+c? \n" ); document.write( "
Algebra.Com's Answer #820762 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "5002 = 2*41*61 = a*b*c \n" ); document.write( "a+b+c=104 \n" ); document.write( "The question asks how many other positive integers are the products of exactly three distinct primes whose sum is also 104. \n" ); document.write( "For the sum of three distinct primes to be 104, one of them has to be 2, so the sum of the other two has to be 102. \n" ); document.write( "So you need to find the number of pairs of primes other than 41 and 61 that also have a sum of 102. \n" ); document.write( "You will learn nothing from this question if we work the whole problem for you, so I leave it to you to finish the problem. \n" ); document.write( "(my answer was 7....) \n" ); document.write( " \n" ); document.write( " |