document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1189404>Question 1189404</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three cards are dealt at random from a standard deck of 52 cards. What is the probability that the first card is a 4, the second card is a club, and the third card is a 2? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #820760 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=820760\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The possibilities are <BR>\n" );
document.write( "4C*Club not 2*2<BR>\n" );
document.write( "4C*2C*2<BR>\n" );
document.write( "look at these. The first has probability of 1/52*12/51*4/50=48/132600<BR>\n" );
document.write( "The second is 1/52*1/51*3/50=3/132600<BR>\n" );
document.write( "4D,4H,4S* club not 2*2<BR>\n" );
document.write( "same*2C*2<BR>\n" );
document.write( "The first is (3/52)(12/13)(4/50)=144/132600<BR>\n" );
document.write( "The second is (3/52)*1/51*(3/50)=9/132600<BR>\n" );
document.write( "the sum is 204/132600=1/650<BR>\n" );
document.write( "-<BR>\n" );
document.write( "rough check using sampling with replacement and ignoring double counting (1/13)(1/4)(1/13)=1/676  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );