document.write( "Question 1189402: Machine A can do a job alone in 10 hours. Machine B can do the same job alone in 12 hours. Machine A is turned on at 6am Machine B is turned on at 9 a.m. Machine A breaks down at 10 a.m., and Machine B must finish the job alone. When will Machine B finish? \n" ); document.write( "
Algebra.Com's Answer #820758 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let's say the task is to inspect 60 items.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Machine A can inspect 60 items in 10 hours. Its unit rate is 60/10 = 6 items per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Machine B can inspect 60 items in 12 hours. Its unit rate is 60/12 = 5 items per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Machine A runs from 6 AM to 10 AM, which is a duration of 4 hours. Over this timespan, the machine inspects 6*4 = 24 items. \n" ); document.write( "This leaves 60-24 = 36 items for Machine B to inspect.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Machine B can inspect 5 items per hour, and must inspect 36 of them. That means it needs 36/5 = 7.2 hours \n" ); document.write( "When dividing the number of items over the unit rate, the \"items\" unit cancels leaving just the hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "7.2 hours = 7 hours + 0.2 hours \n" ); document.write( "7.2 hours = 7 hours + 0.2*60 min \n" ); document.write( "7.2 hours = 7 hours + 12 min\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Machine B needs 7 hours and 12 minutes. \n" ); document.write( "Adding this duration onto 9:00 AM will get us to 16:12 in military time which is equivalent to 4:12 PM\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 4:12 PM \n" ); document.write( " \n" ); document.write( " |