document.write( "Question 1189372: The complex numbers z and w satisfy |z| = |w| = 1 and zw is not equal to -1.\r
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document.write( "(a) Prove that overline{z} = 1/z and overline{w} = 1/w.\r
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document.write( "(b) Prove that (z + w)/(zw + 1) is a real number. \n" );
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Algebra.Com's Answer #820754 by ikleyn(52787)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "The complex numbers z and w satisfy |z| = |w| = 1 and zw is not equal to -1. \n" ); document.write( "(a) Prove that overline{z} = 1/z and overline{w} = 1/w. \n" ); document.write( "(b) Prove that (z + w)/(zw + 1) is a real number. \n" ); document.write( "~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Part (a)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Part (a) is the widely known fact. Students learn it on the beginner steps of studying complex numbers.\r\n" ); document.write( "\r\n" ); document.write( "The proof is very short and straightforward.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Notice, that in part (a), we should prove only first statement for z, since the statement for w is mathematically THE SAME.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " If z = a + bi, then overline(z) = a - bi.\r\n" ); document.write( "\r\n" ); document.write( " If |z| = 1, it means that\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Part (b)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Part (b) is not widely known, which makes it interesting.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Since |z| = 1 and |w| = 1, it means that z and w are the unit vectors of the length 1: their endpoints lie on the unit circle.\r\n" ); document.write( "\r\n" ); document.write( " To calculate (z+w), apply the parallelogram's rule. Since the sides of the parallelogram on vectors z and w are equal,\r\n" ); document.write( "\r\n" ); document.write( " the parallelogram is a rhombus. The sum (z+w) is the diagonal of the parallelogram, and since parallelogram is a rhombus,\r\n" ); document.write( "\r\n" ); document.write( " arg(z+w) is EITHER\r \n" ); document.write( "\n" ); document.write( "At this point, the proof is completed.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |