document.write( "Question 1189402: Machine A can do a job alone in 10 hours. Machine B can do the same job alone in 12 hours. Machine A is turned on at 6am Machine B is turned on at 9 a.m. Machine A breaks down at 10 a.m., and Machine B must finish the job alone. When will Machine B finish? \n" ); document.write( "

Algebra.Com's Answer #820752 by Boreal(15235) $\"\"$ $\"About$

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in 1 hour A can do 1/10 the job and B can do 1/12 the job.
\n" ); document.write( "At 10 am, A has been on the job 4 hours and has done 4/10. B has been on 1 hour and has done (1/12)
\n" ); document.write( "So the amount left to do is 1-(24/60)-(5/60) or 31/60
\n" ); document.write( "31/60/1/12=(31/60)*12=6.2 hours
\n" ); document.write( "10 am +6.2 hours is 4:12 pm
\n" ); document.write( "-
\n" ); document.write( "4 hours of A (4/10)
\n" ); document.write( "7.2 hours of B (7.2/12) \n" ); document.write( "

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