document.write( "Question 112527: Find three consecutive integers such that the product of the first integer and the second integer is 42. \n" ); document.write( "

Algebra.Com's Answer #82075 by checkley71(8403) $\"\"$ $\"About$

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X X+1 X+2 ARE THE 3 NUMBERS.
\n" ); document.write( "X(X+1)=42
\n" ); document.write( "X^2+X-42=0
\n" ); document.write( "(X+7)(X-6)=0
\n" ); document.write( "X+7=0
\n" ); document.write( "X=-7 ANSWER FOR THE FIRST NUMBER. -7+1=-6 IS THE SECOND NUMBER.-7+2=-5 IS THE THIRD NUMBER.
\n" ); document.write( "X-6=0
\n" ); document.write( "X=6 ANSWER FOR THE FIRST NUMBER. 6+1=7 FOR THE SECOND. 6+2=8 FOR THE THIRD.
\n" ); document.write( "-7*-6=42
\n" ); document.write( "42=42
\n" ); document.write( "6*7=42
\n" ); document.write( "42=42\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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