document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=112539>Question 112539</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0618250220/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Hello I'm given a Right Triangle EFG. EF being the hypotenuse with a altitude which is HG. Segment GF=20 and segment EF=25. The question is Find the length of HF. <BR>\n" );
document.write( "I just can't seem to figure this one out I'm not having any trouble on any of the other ones. Well i hope my description is good enough, Thank You.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82073 by </B><A HREF=/tutors/aboutme.mpl?userid=ilana><B>ilana(307)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ilana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82073\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The trick to this is you need to realize that EFG and GFH are similar triangles.  This is because the angle at F is shared by both and angles G and H are both right angles (an altitude meets the opposite side at a right angle).  So the remaining angles, E and G, must be the same, too, to add to 180 degrees.<BR>\n" );
document.write( "(You could also use the angle, side, angle method of seeing similar triangles)<BR>\n" );
document.write( "With similar triangles, setting up a proportion helps you solve for the lengths.  So GF/EF = HF/GF.  Using the numbers we have, 20/25 = x/20.  Cross multiply to get 25x=400, so x=16.  That is the length of HF. </SPAN>\n" );
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