document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1189346>Question 1189346</A>: <I><SPAN STYLE=\"word-break: break-all;\"> * Show your complete solution<BR>\n" );
document.write( "* Explain your answer after the solution<BR>\n" );
document.write( "1. A shipment  of 10 TV sets contains 3  defective units. If three units are taken for inspection, then what is the probability that:<BR>\n" );
document.write( "a. all the defective TV sets are included<BR>\n" );
document.write( "b. no defective TV set shall be included<BR>\n" );
document.write( "c. only one of the defective TV sets shall be included </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #820718 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=820718\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The chance of the first TV being defective is 3/10. Now there are 9 left of which 2 are defective, so the probability is 2/9. Then 1/8.<BR>\n" );
document.write( "In the second it is 7/10 for the first, 6/9 for the second, and 5/8 for the third.<BR>\n" );
document.write( "With only one of the TVs, it can happen with the first, second, or third with equal probability, so you need a 3. Then multiply that 3 by one possibility, such as the first one (3/10) then 7/9, not defective with 7 of them and 9 left, and 6/8.\r<BR>\n" );
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document.write( "a. 3/10*(2/9)(1/8)=6/720=1/120<BR>\n" );
document.write( "b. (7/10)(6/9)(5/8)=210/720 or 7/24<BR>\n" );
document.write( "c. 3*(3/10)(7/9)(6/8)=378/720=21/40; three ways to have the defective TV included<BR>\n" );
document.write( "This is also 3C1*7C2/10C3=3*21/120=21/40 </SPAN>\n" );
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