document.write( "Question 1189356: Find the equation of the circle whose center is on the line 2x - y + 4 = 0 and which passes thru the points (0,4)
\n" ); document.write( "and (3,7)
\n" ); document.write( "a. (x-7)^2 + (y-3)^2 = 8
\n" ); document.write( "b. (x-2)^2 + (y-3)^2 = 7
\n" ); document.write( "c. (x-7)^2 + (y-4)^2 = 6
\n" ); document.write( "d. (x-1)^2 + (y-6)^2 = 5
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Algebra.Com's Answer #820701 by Alan3354(69443)\"\" \"About 
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Find the equation of the circle whose center is on the line 2x - y + 4 = 0 and which passes thru the points A(0,4) and B(3,7)
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\n" ); document.write( "The slope of AB is +1.
\n" ); document.write( "The center has to be on the perpendicular bisector of the line thru the 2 points.
\n" ); document.write( "The midpoint of AB is (1.5,5.5) and it's slope is -1.
\n" ); document.write( "y-5.5 = -1*(x-1.5) = -x + 1.5
\n" ); document.write( "y = -x + 7
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\n" ); document.write( "The center is the intersection of the 2 lines.
\n" ); document.write( "2x - y + 4 = 0
\n" ); document.write( "y = 2x+4
\n" ); document.write( "y = -x + 7
\n" ); document.write( "---
\n" ); document.write( "2x+4 = -x+7
\n" ); document.write( "3x = 3
\n" ); document.write( "x = 1, y = 6 ----> center is (1,6)
\n" ); document.write( "r = the distance from the center to either point.
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\n" ); document.write( "Choice d. r = 5
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\n" ); document.write( "There's no good reason for having 4 (or any #) of choices.
\n" ); document.write( "The problem should be, \"Find the equation of the circle.\"
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