document.write( "Question 112478: A merchant mixed 30 lb. of peanuts with 20 lbs of cashews. The 50 lb mixture sells for $203. A second mixture included 40lb of peanuts and 60 lbs of cashews. The 100 lb mixture sells for $484. Find the cost per pound of cashews. \n" ); document.write( "
Algebra.Com's Answer #82070 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=cost per pound of peanuts \n" ); document.write( "And let y=cost per pound of cashews\r \n" ); document.write( "\n" ); document.write( "Now we are told the following: \n" ); document.write( "30x+20y=$203-----------------------eq1 \n" ); document.write( "and \n" ); document.write( "40x+60y=$484--------------------------eq2\r \n" ); document.write( "\n" ); document.write( "Divide each term in eq2 by 4\r \n" ); document.write( "\n" ); document.write( "10x+15y=$121-------------------eq2a\r \n" ); document.write( "\n" ); document.write( "Now multiply eq2a by 3 \n" ); document.write( "30x+45y=$363--------------------eq2b\r \n" ); document.write( "\n" ); document.write( "subtract eq1 from eq2b:\r \n" ); document.write( "\n" ); document.write( "25y=$160 divide both sides by 25\r \n" ); document.write( "\n" ); document.write( "y=$6.40 -------cost per pound of cashews\r \n" ); document.write( "\n" ); document.write( "substituting into eq2a, we get:\r \n" ); document.write( "\n" ); document.write( "10x+15($6.40)=$121 \n" ); document.write( "10x+$96=$121 subtract $96 from both sides\r \n" ); document.write( "\n" ); document.write( "10x=$25 divide both sides by 10 \n" ); document.write( "x=$2.50----------------cost per pound of peanuts\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "30(2.50)+20(6.40)=203\r \n" ); document.write( "\n" ); document.write( "75+128=203 \n" ); document.write( "203=203 \n" ); document.write( "and \n" ); document.write( "40(2.50)+60(6.40)=484 \n" ); document.write( "100+384=484 \n" ); document.write( "484=484\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps--ptaylor\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |