document.write( "Question 112478: A merchant mixed 30 lb. of peanuts with 20 lbs of cashews. The 50 lb mixture sells for $203. A second mixture included 40lb of peanuts and 60 lbs of cashews. The 100 lb mixture sells for $484. Find the cost per pound of cashews. \n" ); document.write( "
Algebra.Com's Answer #82070 by ptaylor(2198)\"\" \"About 
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Let x=cost per pound of peanuts
\n" ); document.write( "And let y=cost per pound of cashews\r
\n" ); document.write( "\n" ); document.write( "Now we are told the following:
\n" ); document.write( "30x+20y=$203-----------------------eq1
\n" ); document.write( "and
\n" ); document.write( "40x+60y=$484--------------------------eq2\r
\n" ); document.write( "\n" ); document.write( "Divide each term in eq2 by 4\r
\n" ); document.write( "\n" ); document.write( "10x+15y=$121-------------------eq2a\r
\n" ); document.write( "\n" ); document.write( "Now multiply eq2a by 3
\n" ); document.write( "30x+45y=$363--------------------eq2b\r
\n" ); document.write( "\n" ); document.write( "subtract eq1 from eq2b:\r
\n" ); document.write( "\n" ); document.write( "25y=$160 divide both sides by 25\r
\n" ); document.write( "\n" ); document.write( "y=$6.40 -------cost per pound of cashews\r
\n" ); document.write( "\n" ); document.write( "substituting into eq2a, we get:\r
\n" ); document.write( "\n" ); document.write( "10x+15($6.40)=$121
\n" ); document.write( "10x+$96=$121 subtract $96 from both sides\r
\n" ); document.write( "\n" ); document.write( "10x=$25 divide both sides by 10
\n" ); document.write( "x=$2.50----------------cost per pound of peanuts\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "30(2.50)+20(6.40)=203\r
\n" ); document.write( "\n" ); document.write( "75+128=203
\n" ); document.write( "203=203
\n" ); document.write( "and
\n" ); document.write( "40(2.50)+60(6.40)=484
\n" ); document.write( "100+384=484
\n" ); document.write( "484=484\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps--ptaylor\r
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