document.write( "Question 1189325: A conic has an equation of an asymptote equal to 3x=4y. What is the equation of the conic having its center at
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\n" ); document.write( "a. 9x2-16y2 = 144
\n" ); document.write( "b. 16x2 - 9y2 = 144
\n" ); document.write( "c. 9y2 - 16x2 = 144
\n" ); document.write( "d. 16y2 - 9x2 = 144
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Algebra.Com's Answer #820676 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "check the first choice:\r
\n" ); document.write( "\n" ); document.write( "\"9x%5E2-16y%5E2+=+144+\"\r
\n" ); document.write( "\n" ); document.write( "\"9x%5E2%2F144-16y%5E2%2F144+=+144%2F144+\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F16-y%5E2%2F9+=+144%2F144+\"\r
\n" ); document.write( "\n" ); document.write( "=> \"h=0\", \"k=0\", \"a=4\",\"b=3\"\r
\n" ); document.write( "\n" ); document.write( "=> center (\"h\", \"k\" ) is at origin \r
\n" ); document.write( "\n" ); document.write( "The transverse axis is a line segment that passes through the center of the hyperbola and has vertices as its endpoints.\r
\n" ); document.write( "\n" ); document.write( "The vertices (\"h%2Ba\", \"k\" ), (\"h-a\",\"+k\" ) are the two bending points of the hyperbola with center (\"h\", \"k\" ) and semi-axis \"a\", \"b\".\r
\n" ); document.write( "\n" ); document.write( "so,\r
\n" ); document.write( "\n" ); document.write( "(\"h%2Ba\", \"k\" )= (\"0%2B4\",\"+0\" ) =(\"4\",\"0\")\r
\n" ); document.write( "\n" ); document.write( "(\"h-a\", \"k+\")=(\"0-4\",\"0\")=(\"-4\",\"0\")\r
\n" ); document.write( "\n" ); document.write( "so, vertices lie on x-axis, and \"y=0\"->and its transverse axis lies between (\"4\",\"0\") and (\"-4\",\"0\")\r
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\n" ); document.write( "\n" ); document.write( "For right-left hyperbola the asymptotes are:\r
\n" ); document.write( "\n" ); document.write( "\"y\"= ±\"%28b%2Fa%29%28x-h%29%2Bk\"\r
\n" ); document.write( "\n" ); document.write( "we need only positive\r
\n" ); document.write( "\n" ); document.write( "\"y=+%283%2F4%29%28x-0%29%2B0\"\r
\n" ); document.write( "\n" ); document.write( "\"y=+3x%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"+3x=4y\"\r
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\n" ); document.write( "\n" ); document.write( "this means, your answer is option a. \"9x%5E2-16y%5E2+=+144+\"\r
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