document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1189333>Question 1189333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 1 cm less than three times the width if the perimeter is 54 cm find the dimensions of the rectangle use the formula to find the dimension P=2l+2w </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #820670 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=820670\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 1 cm less than three times the width if the perimeter is 54 cm find the dimensions of the rectangle<BR>\n" );
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document.write( "L = 3W-1<BR>\n" );
document.write( "2W+2L = 54<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Sub for L:<BR>\n" );
document.write( "2W + 2(3W-1) = 54<BR>\n" );
document.write( "Solve for W, then for L </SPAN>\n" );
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