document.write( "Question 1189319: The denominator of a fraction is 11 more than the numerator. If both the numerator and the denominator are decreased by 1 ​, the resulting fraction is equivalent to 3/14 . Find the fraction.
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Algebra.Com's Answer #820652 by josgarithmetic(39617)\"\" \"About 
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The first fraction, \"x%2F%28x%2B11%29\"\r
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\n" ); document.write( "\n" ); document.write( "The changed fraction, \"%28x-1%29%2F%28x%2B10%29\"\r
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\n" ); document.write( "\n" ); document.write( "The changed fraction is equal to \"3%2F14\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%2F%28x%2B10%29=3%2F14\"\r
\n" ); document.write( "\n" ); document.write( "\"14%28x-1%29=3%28x%2B10%29\"\r
\n" ); document.write( "\n" ); document.write( "\"14x-14=3x%2B30\"\r
\n" ); document.write( "\n" ); document.write( "\"11x=30%2B14\"\r
\n" ); document.write( "\n" ); document.write( "\"11x=44\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=4%29\"\r
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\n" ); document.write( "\n" ); document.write( "The first fraction was \"highlight%284%2F15%29\"
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