document.write( "Question 112537: A picture measures 5 inches by 7 inches. The picture is enlarged to a size of 15 inches by 21 inches.\r
\n" ); document.write( "\n" ); document.write( "A. What are the area and perimeter of the original picture?\r
\n" ); document.write( "\n" ); document.write( "B. What are the area and perimeter of the enlarged picture?\r
\n" ); document.write( "\n" ); document.write( "C. What is the percent of increase of the area of the enlarged picture?
\n" ); document.write( "

Algebra.Com's Answer #82064 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
A) AREA=5*7=35 IN^2
\n" ); document.write( "PERIMETER=2*5+2*7=10+14=24 INCHES.
\n" ); document.write( "B) AREA=15*21=315 IN^2.
\n" ); document.write( "PERIMETER=2*15+2*21=30+42=72 INCHES.
\n" ); document.write( "C) INCREASE IN AREA=315-35=280 IN^2.
\n" ); document.write( "OR (280-35)/35=7 OR 700% INCREASE IN AREA.
\n" ); document.write( "
\n" );