document.write( "Question 1189297: Hi
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document.write( "Stephen and Siew mei had $540 altogether. Stephen gave 1/7 of his money siew mei. In return siew mei gave 1/4 of the total amount she had to Stephen . Then they both had the same amount of money. How much did Stephen had at first.\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #820637 by greenestamps(13198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "There are many ways to set up this problem for solving. The solution from the other tutor is fine, and is a very typical solution. \n" ); document.write( "I personally would choose a different starting point by looking ahead at the transactions to perhaps make the algebra required for solving the problem a bit easier. \n" ); document.write( "Specifically, since in the first transaction Stephen gives 1/7 of his money to Siew Mei, I would start with \n" ); document.write( "let 7x = amount Stephen starts with \n" ); document.write( "then 540-7x = amount Siew Mei starts with \n" ); document.write( "In the first transaction, Stephen gives 1/7 of his money, x, to Siew Mei. The amounts the two have are now 6x for Stephen and 540-6x for Siew Mei. \n" ); document.write( "Next Siew Mei gives 1/4 of her money, 135-1.5x, to Stephen. The amounts they have are now 135+4.5x for Stephen and 405-4.5x for Siew Mei. \n" ); document.write( "The amounts they have now are the same, so they are both half of $540, which is $270. So we can either solve the equation that says those two expressions are equal; or we can solve an equation that says one of those two expressions is equal to 540/2=270. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER: The amount Stephen started with was 7x=$210 \n" ); document.write( " \n" ); document.write( " |