document.write( "Question 1189297: Hi
\n" ); document.write( "Stephen and Siew mei had $540 altogether. Stephen gave 1/7 of his money siew mei. In return siew mei gave 1/4 of the total amount she had to Stephen . Then they both had the same amount of money. How much did Stephen had at first.\r
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Algebra.Com's Answer #820628 by ikleyn(52778) $\"\"$ $\"About$

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\n" ); document.write( "Stephen and Siew Mei had $540 altogether.
\n" ); document.write( "Stephen gave 1/7 of his money Siew Mei.
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\n" ); document.write( "Then they both had the same amount of money. How much did Stephen had at first ?
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document.write( "Let x be the amount which Stephan had at first.\r\n" );
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document.write( "Then Siew Mei had (540-x) dollars at first.\r\n" );
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document.write( "When Stephen gave 1/7 of his money to Siew Mei, Stephen left with  dollars;\r\n" );
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document.write( "Siew Mei had .\r\n" );
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document.write( "When Siew Mei gave 1/4 of the total amount she had to Stephen, she left with .\r\n" );
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document.write( "Stephen had finally  +  dollars.\r\n" );
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document.write( "The final amounts are the same, so we write this equation\r\n" );
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document.write( "     =  + .\r\n" );
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document.write( "Simplify this equation and find x. First multiply both sides by 4*7 = 28\r\n" );
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document.write( "    3*7*((540-x) + (1/7)*x) = 6*4x + 7*((540-x)+(1/7)x)\r\n" );
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document.write( "    21*(540-x) + 3x = 24x + 7*(540-x) + x\r\n" );
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document.write( "    14*(540-x) = 22x\r\n" );
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document.write( "    14*540 = 22x + 14x\r\n" );
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document.write( "    14*540 = 36x\r\n" );
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document.write( "    x =  = 210.\r\n" );
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document.write( "ANSWER.  Stephen had initially 210 dollars;  Siew Mei had initially 540-210 = 330 dollars.\r\n" );
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document.write( "CHECK.  After first giving, Stephen had 210-30 = 180 dollars; Siew Mei had 330+30 = 360 dollars.\r\n" );
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document.write( "        After second giving, Stephen had 180 + 90 = 270 dollars; Siew Mei had 360-90 = 270 dollars.   ! Equal amounts, correct !\r\n" );
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