document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=112530>Question 112530</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three consecutive numbers such that twice the square of the first number is 38 more than the product of the other two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82062 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82062\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET X, (X+1) & (X+2) BE THE 3 CONSECUTIVE NUMBERS.<BR>\n" );
document.write( "2X^2=38+(X+1)(X+2)<BR>\n" );
document.write( "2X^2=38+X^2+3X+2<BR>\n" );
document.write( "2X^2-X^2-3X-38-2=0<BR>\n" );
document.write( "X^2-3X-40=0<BR>\n" );
document.write( "(X-8)(X+5)=0<BR>\n" );
document.write( "X-8=0<BR>\n" );
document.write( "X=8 ANSWER. 8+1=9 8+2=10.<BR>\n" );
document.write( "X+5=0<BR>\n" );
document.write( "X=-5 ANSWER. -5+1=-4 -5+2=-3.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "2(8)^2=38+(9*10)<BR>\n" );
document.write( "2*64=38+90<BR>\n" );
document.write( "128=128<BR>\n" );
document.write( "----------------------<BR>\n" );
document.write( "2(-5)^2=38+(-4*-3)<BR>\n" );
document.write( "2*25=38+12<BR>\n" );
document.write( "50=50<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );