document.write( "Question 1189231: t
\n" ); document.write( "he center of a suspension bridge forms a parabolic arc. The cable is suspended from the top of the support
\n" ); document.write( "towers, which are 800 ft apart. The top of the towers 170 ft above the road and the lowest point on the cable is
\n" ); document.write( "midway between the towers and 10 ft above the road. Find the height of the cable above the road at a distance of
\n" ); document.write( "100 ft from the towers
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Algebra.Com's Answer #820536 by Alan3354(69443)\"\" \"About 
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the center of a suspension bridge forms a parabolic arc. The cable is suspended from the top of the support towers, which are 800 ft apart.
\n" ); document.write( "The top of the towers 170 ft above the road and the lowest point on the cable is
\n" ); document.write( "midway between the towers and 10 ft above the road.
\n" ); document.write( "Find the height of the cable above the road at a distance of 100 ft from the towers
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\n" ); document.write( "A parabola has the form y = ax^2 + bx + c
\n" ); document.write( "Find the parabola with its vertex at (0,0) and the towers at (-400,0) and (400,0).
\n" ); document.write( "Add the 10 feet later.
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\n" ); document.write( "0 = 0*a + 0*b + c ---> c = 0
\n" ); document.write( "160 = a*(-400)^2 + b*(-400)
\n" ); document.write( "160 = a*(400)^2 + b*(400)
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\n" ); document.write( "160 = 160000a - 400b
\n" ); document.write( "160 = 160000a + 400b
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\n" ); document.write( "0 = -800b ---> b = 0
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\n" ); document.write( "160 = 160000a
\n" ); document.write( "a = 1/1000
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\n" ); document.write( "y = x^2/1000 + 10 is the equation of the cable
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\n" ); document.write( "For 100 feet from the towers and between the towers:
\n" ); document.write( "At x = 300:
\n" ); document.write( "y = 90000/1000 + 10 = 100 feet\r
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